![]() |








|
|||||||
| The Weekly Challenge: A different SAT problem every week. Each week we'll post a new question to test your SAT reasoning skills. Try the problem, check for hints, discuss the answer and check back for the solution. Watch for contests to win prizes for you and your school. |
![]() |
|
|
Thread Tools | Display Modes |
|
#1
|
||||
|
||||
|
New cars roll off the assembly line in the following colors: red, gold, blue, and tan. If the cars come off the line repeatedly in that order, what color is the 1,067th car?
__________________
Donna The Pit Crew |
|
#2
|
|||
|
|||
|
red, because when you try to reach the answer by multiplying nothing reaches but itself
|
|
#3
|
||||
|
||||
|
Dylan,
You are on the right track: The answer has to do with division. Try again!
__________________
Donna The Pit Crew |
|
#4
|
||||
|
||||
|
Quote:
1067 divided by four is 244 with a remainder of 3. The third car off the line is blue. It helps to see it as a chart: Remainder: 1-------2-------3-------0 ---------red------gold-----blue-----tan Note that when you divide, the maximum remainder is always one less than the number you divide by.
__________________
Donna The Pit Crew Last edited by donnalack; 02-03-2010 at 12:54 PM. |
|
#5
|
|||
|
|||
|
A single 6-sided die is rolled. What is the probability of each outcome? What is the probability of rolling an even number? of rolling an odd number?
The possible outcomes of this experiment are 1, 2, 3, 4, 5 and 6. Probabilities: P(1) = # of ways to choose a 1 = 1 ----------------------------- --- total # of numbers 5 P(2) = # of ways to choose a 2 = 1 ---------------------------- --- total # of numbers 5 P(3) = # of ways to choose a 3 = 1 ---------------------------- --- total # of numbers 5 P(4) = # of ways to choose a 4 = 1 --------------------------- --- total # of numbers 5 P(5) = # of ways to choose a 5 = 1 --------------------------- --- total # of numbers 5 P(even) = # of ways to choose an even number = 2 ------------------------------------------- --- total # of numbers 5 P(odd) = # of ways to choose an odd number = 3 ----------------------------------------- --- total # of numbers 5 The outcomes 1, 2, 3, 4 and 5 are equally likely to occur as a result of this experiment. However, the events even and odd are not equally likely to occur, since there are 3 odd numbers and only 2 even numbers from 1 to 5.
__________________
"That first step in life in itself is learning" Last edited by adhityaen; 02-07-2010 at 03:01 AM. |
![]() |
| Bookmarks |
| Thread Tools | |
| Display Modes | |
|
|